smallest 3 digit number divisible by 6 8 12|Class 6 Maths : Baguio So, the smallest three digit multiple of 24 will be, 100 = (100 – 4) + 24 = 96 + 24 = 120. Hence, the smallest 3-digit number which is exactly divisible by 6, 8, and 12, is 120. . Update (October 10th, 2018): My BPI Express Start Credit Card is turning a year now and I was able to apply and got approved with RCBC Bankard and Citibank with it as my reference. Since I already have two regular credit cards, I’m planning to request for a release of the holdout money and retention of the card. Hope everything goes well.
smallest 3 digit number divisible by 6 8 12,Now we will divide the smallest 3-digit number with the LCM obtained, and the remainder will be subtracted from the dividend, and 24 will be added to it to make it perfectly divisible. ∴ 100 24 = 4, Remainder = 4. According to the above statement. = (100 – 4) + 24 = 96 .So, the smallest three digit multiple of 24 will be, 100 = (100 – 4) + 24 = 96 + 24 = 120. Hence, the smallest 3-digit number which is exactly divisible by 6, 8, and 12, is 120. .We have to find the smallest $$3$$-digit multiple of $$24$$. It can be seen that $$24\times 4=96$$ and $$24\times 5=120$$. Hence, the smallest $$3$$-digit number which is . Determinethe smallest 3-digit number which is exactly divisible by 6, 8 and 12.Class: 6Subject: MATHSChapter: PLAYING WITH NUMBERSBoard:CBSEYou can .
LCM of 6, 8 and 12 = 2×2×2×3 = 24. The smallest 3-digit number = 100. To find the smallest 3-digit number possible we have to look for smallest 3-digit multiples of 24. .
The smallest 3-digit number which is exactly divisible by 6, 8, and 12 is 120. In Mathematics, the LCM is the value which is evenly divisible by the given two .smallest 3 digit number divisible by 6 8 12Smallest number = LCM of 6, 8, 12. We have to find the smallest 3-digit multiple of 24. It can be seen that. 24 4 = 96 and. 24 5 = 120. Hence, the smallest 3-digit number which .
Question. Determine the smallest 3− digit number which is exactly divisible by 6, 8 and 12. Solution. Verified by Toppr. Smallest number divisible by 6, 8, 12 = L.C.M of 6, 8, .
Hence, the smallest 3-digit number which is exactly divisible by 6, 8 and 12 is 120. This is the required answer. Note: In such types of questions it is always advisable .
Solution: The smallest 3-digit number which is exactly divisible by 6, 8 and 12 is 120. Here, we have to find the smallest 3-digit number which is exactly divisible by 6, 8 and 12. . Smallest three digit number divisible by 6 8 12Determine the smallest 3-digit number which is exactly divisible by 6, 8 and 12. Q. Question 5. Determine the largest 3-digit number which is exactly divisible by 8, 10 and 12. Q. The greatest 4-digit number exactly divisible by 10, 15, 20 is. View More.Class 6 Maths Now, 120 × 8 = 960 and 120 × 9 = 1080. We see that 120 × 9 = 1080 is a 4-digit number but, we need the greatest 3-digit multiple. Therefore, the greatest 3-digit multiple of 120 is 120 × 8 = 960 i.e, 960. Hence, the greatest 3-digit number exactly divisible by 8, 10, and 12 is 960. You can also use the LCM Calculator to solve this. In general, to test divisibility by any natural number of the form 2ⁿ, we only have to examine its last n digits and check if they form a number that is divisible by 2ⁿ.In particular: Divisibility test of 2. A number is divisible by 2 if and only if its last digit is even, i.e., divisible by 2.In other words, the last digit must be equal to 0, 2, 4, 6, or 8.C. 100004. D. 100002. Solution. Verified by Toppr. We know that the divisibility test of 6 states that a number is divisible by 6 if the number is even and the sum of the digits is divisible by 3. Hence, 100002 is the smallest number divisible by 6 as it is even and the sum of digits 1+0+0+0+0+2 =3.The sum of all 3-digit numbers divisible by 8 is 61376. What is the smallest three digit number divisible by 8? The smallest or lowest 3-digit number divisible by 8 is the first number on the list above (first 3 digit number divisible by 8). As you can see, that number is 104. What is the largest three digit number divisible by 8?We know that largest 3-digit number is 999. Dividing 999 by 120 we get. ⇒ 999 = 120 × 8 + 39. If we subtract the remainder from 999 we get the largest 3-digit number which is multiple of 120. ⇒ 120 × 8 = 999-39 = 960. i.e. 960 is the largest 3-digit number which is multiple of 120. Hence, the largest 3-digit number which is exactly .
The smallest or lowest 3-digit number divisible by 12 is the first number on the list above (first 3 digit number divisible by 12). As you can see, that number is 108. What is the largest three digit number divisible by 12? The largest or greatest 3-digit number divisible by 12 is the last number on the list above (last 3 digit number divisible .
The integer must be divisible by 2 and 3 in order to be divided by 6. The criterion is that for an integer of 8, the last three digits must be divisible by 8. The integer must be divisible by 3 and 4 in order to be divided by 12. So, we have to first find the LCM of 6,8 and 12. This is given by-The LCM is the product of the prime factors obtained. Step 3: Calculate the LCM. Finally, we can calculate the LCM by multiplying the highest powers of the prime factors: LCM = 2^3 * 3^1 = 8 * 3 = 24. Step 4: Finding the smallest 3-digit number divisible by 6, 8, and 12. Now that we have the LCM, we need to find the smallest 3-digit number that is divisible by 24.
Determinethe smallest 3-digit number which is exactly divisible by 6, 8 and 12.Class: 6Subject: MATHSChapter: PLAYING WITH NUMBERSBoard:CBSEYou can ask any d.
LCM of 6, 8 and 12 = 2×2×2×3 = 24. The smallest 3-digit number = 100. To find the smallest 3-digit number possible we have to look for smallest 3-digit multiples of 24. Multiples of 24 = 24, 48, 72, 96, 120, 144. Clearly, 120 is the smallest 3-digit multiple of 24. Therefore, the required number is 120.
smallest 3 digit number divisible by 6 8 12 Class 6 Maths The smallest 3-digit number which is exactly divisible by 6, 8 and 12 is 120. Here, we have to find the smallest 3-digit number which is exactly divisible by 6, 8 and 12. Prime factorization of 6, 8, 12 is given by, LCM = 2 × 2 × 2 × 3 = 24. The multiples of 24 are, 24 × 1 = 24 24 × 2 = 48 24 × 3 = 72 24 × 4 = 96 24 × 5 = 120 24 × 6 = 144A number is divisible by 4 if the number consisting of its last two digits is divisible by 4. A number is divisible by 5 if its last digit is a 5 or a 0. A number is divisible by 6 if it is divisible by 2 and 3, i.e. if it is even and its sum and digits are divisible by 3. A number is divisible by 8 if its last three digits are divisible by 8 .LCM = 2 × 2 × 2 × 3 = 24. We have to find the smallest 3-digit multiple of 24. It can be seen that 24 × 4 = 96 and 24 × 5 = 120. Hence, the smallest 3-digit number which is exactly divisible by 6, 8, and 12 is 120. Question From - NCERT Maths Class 6 Chapter 3 EXERCISE 3.7 Question – 4 PLAYING WITH NUMBERS CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-Determine the smal.
The smallest 3-digit multiple of 24 = 24 × 5 = 120 Therefore, 120 is the smallest 3 - digit number which is exactly divisible by 6 , 8 and 12 . Suggest CorrectionsGiven : The given numbers are 6, 8, 12. To do : We have to find the smallest three digit number which is divisible by 6, 8, 12. Solution : The smallest 3-digit which is exactly divisible by 6,8 and 12 will be a multiple of LCM of 6,8 and 12.
smallest 3 digit number divisible by 6 8 12|Class 6 Maths
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